x^2-9x+14/4x-5=o

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Solution for x^2-9x+14/4x-5=o equation: 


x in (-oo:+oo)

x^2-(9*x)+(14/4)*x-5 = o // - o

x^2-o-(9*x)+(14/4)*x-5 = 0

x^2-o-9*x+(14/4)*x-5 = 0

x^2-o-11/2*x-5 = 0

DELTA = (-11/2)^2-(1*4*(-o-5))

DELTA = 4*(o+5)+121/4

4*(o+5)+121/4 = 0

(4^2*(o+5))/4+121/4 = 0

4^2*(o+5)+121 = 0

16*o+201 = 0

(16*o+201)/4 = 0

(16*o+201)/4 = 0 // * 4

16*o+201 = 0

16*o+201 = 0 // - 201

16*o = -201 // : 16

o = -201/16

DELTA = 0  <=>  t_1 = -201/16

x = 11/2/(1*2) i o = -201/16

x = 11/4 i o = -201/16

( x = ((4*(o+5)+121/4)^(1/2)+11/2)/(1*2) or x = (11/2-(4*(o+5)+121/4)^(1/2))/(1*2) ) i o > -201/16

( x = ((4*(o+5)+121/4)^(1/2)+11/2)/2 or x = (11/2-(4*(o+5)+121/4)^(1/2))/2 ) i o > -201/16

o-(-201/16) > 0

o+201/16 > 0

o+201/16 > 0 // - 201/16

o > -201/16

x in { 11/4, ((4*(o+5)+121/4)^(1/2)+11/2)/2, (11/2-(4*(o+5)+121/4)^(1/2))/2 }

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